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Need help with Chemistry Homework

Started by Bakonator, Sep 20, 2015, 03:23 AM

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Bakonator

Sep 20, 2015, 03:23 AM Last Edit: Sep 20, 2015, 03:29 AM by Bakonator
If anyone can help it would be lovely

Al-47 (47.3417 amu) and Al-46 (46.3344 amu) are two natural occruring isotopes in Aluminium. Find the natural abundance of these isotopes?

I dont know how to even solve this right, so if you can help me it would be lovely.






P.S : this is for an AP class I'm taking, so it's ok if no one can come up with the answer, I'll probably have to abandon it and let the teacher correct it :d

lioneatszebra

(weight of isotope 1) (abundance of isotope 1[which you don't know]) + (weight of isotope 2) (abundance of isotope 2[which you don't know]) = average atomic weight

First you do this:

(47.3417)(1-x) + (46.3344) (x) = 26.981539

Then,

47.3417 - 47.3417x + 46.3344x = 26.981539

-47.3417x + 46.3344x = -47.3417 + 26.981539

-1.0073x = -20.360161


I could be wrong. I think I went wrong somewhere, but I'm pretty sure the italicized equation is correct. Someone else needs to verify first. Sorry!

brb, living offline

Bakonator

That seems about right.....since I don't have the answer myself, I'll keep this as a possible answer, thanks for helping :D

Dogggeh

Quote from: djkirsh on Sep 20, 2015, 04:50 AM(weight of isotope 1) (abundance of isotope 1[which you don't know]) + (weight of isotope 2) (abundance of isotope 2[which you don't know]) = average atomic weight

First you do this:

(47.3417)(1-x) + (46.3344) (x) = 26.981539

Then,

47.3417 - 47.3417x + 46.3344x = 26.981539

-47.3417x + 46.3344x = -47.3417 + 26.981539

-1.0073x = -20.360161


I could be wrong. I think I went wrong somewhere, but I'm pretty sure the italicized equation is correct. Someone else needs to verify first. Sorry!




I believe you are correct, just make sure you have the full workings bakonator

Bakonator

Quote from: Dogggeh on Sep 20, 2015, 11:42 AM
Quote from: djkirsh on Sep 20, 2015, 04:50 AM(weight of isotope 1) (abundance of isotope 1[which you don't know]) + (weight of isotope 2) (abundance of isotope 2[which you don't know]) = average atomic weight

First you do this:

(47.3417)(1-x) + (46.3344) (x) = 26.981539

Then,

47.3417 - 47.3417x + 46.3344x = 26.981539

-47.3417x + 46.3344x = -47.3417 + 26.981539

-1.0073x = -20.360161


I could be wrong. I think I went wrong somewhere, but I'm pretty sure the italicized equation is correct. Someone else needs to verify first. Sorry!




I believe you are correct, just make sure you have the full workings bakonator

Since I don't know the true answer, i do believe it's correct though :P. Thanks for helping, I'll leave it open if anyone else wanna help, then I'll lock it

tree43

No one has replied recently so locking. If you want it unlocked just message me @Bakonator
(i think you may be able to unlock it but if you cant then message me)